A Closely wound flat circular coil of 50 turns wound flat circular coil of 50 turns has a diameter of 10 cm carries a current of 4 ampere. Determine the magnetic induction at center of coil.
Solution:
Given:
No. of turns : n = 50
Diameter of coil : d = 10 cm = 0.1 m
Current through coil : I = 4 A
The magnetic induction at center of current carrying coil can be given as
B = ( μo n I ) / ( 2 r )
Where, r is the radius of coil
B = ( μo n I ) / d
Putting values we get,
B = ( 4 π X 10-7 X 50 X 4 )
B = 2.513 10-4 T
The magnetic induction at a center of coil of 50 turns and 10 cm diameter carrying a current of 4 ampere is
B = 2.513 10-4 T
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